Subscribing a customer to one or more prices (or plans)

For your convenience, dj-stripe provides a djstripe.models.Customer.subscribe method that will try to charge the customer immediately unless you specify charge_immediately=False

# Recommended Approach to use items dict with Prices
## This will subscribe <customer> to both <price_1> and <price_2>
price_1 = Price.objects.get(nickname="one_price")
price_2 = Price.objects.get(nickname="two_price")
customer = Customer.objects.first()
customer.subscribe(items=[{"price": price_1}, {"price": price_2}])

## This will subscribe <customer> to <price_1>
price_1 = Price.objects.get(nickname="one_price")
customer = Customer.objects.first()
customer.subscribe(items=[{"price": price_1}])

Alternate Approach 1 (with legacy Plans)

## (Alternate Approach) This will subscribe <customer> to <price_1>
price_1 = Price.objects.get(nickname="one_price")
customer = Customer.objects.first()
customer.subscribe(price=price_1)

# If you still use legacy Plans...
## This will subscribe <customer> to both <plan_1> and <plan_2>
plan_1 = Plan.objects.get(nickname="one_plan")
plan_2 = Plan.objects.get(nickname="two_plan")
customer = Customer.objects.first()
customer.subscribe(items=[{"plan": plan_1}, {"plan": plan_2}])

## This will subscribe <customer> to <plan_1>
plan_1 = Plan.objects.get(nickname="one_plan")
customer = Customer.objects.first()
customer.subscribe(items=[{"plan": plan_1}])

Alternate Approach 2

## (Alternate Approach) This will subscribe <customer> to <plan_1>
plan_1 = Plan.objects.get(nickname="one_plan")
customer = Customer.objects.first()
customer.subscribe(plan=plan_1)

However in some cases subscribe() might not support all the arguments you need for your implementation. When this happens you can just call the official stripe.Customer.subscribe().

Tip

Checkout this example and this.

Note that PaymentMethods can be used instead of Cards/Source by substituting

# Add the payment method customer's default
customer.add_payment_method(payment_method)

instead of

# Add the source as the customer's default card
customer.add_card(stripe_source)
in the above example.